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3. I have 4 identical math books, 3 identical English books, and 2 identical French books.

 

(b) In how many ways can I arrange all of them on a bookshelf and French books on the end?

 Jan 29, 2021
 #1
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7*6*5*4*3*2/4/3/2/3/2 = 35 ways. 

I hope this helped. :)))

 

=^._.^=

 Jan 30, 2021
 #2
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Why do we need to 2/4/3/2/3/2

Guest Jan 30, 2021
 #3
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/4/3/2 is because the 4 math books are the same. 

So there 4*3*2 ways the arrange 4 seperate things, but since all of them are the same, we divide 4, 3, and 2. 

Same with 3/2 because the 3 english books are the same. 

I'm sorry, I'm not a teacher nor good at explaining. 

If you're still confused, here's a video: https://www.khanacademy.org/math/precalculus/x9e81a4f98389efdf:prob-comb/x9e81a4f98389efdf:combinations/v/introduction-to-combinations

 

=^._.^=

catmg  Jan 30, 2021

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