We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
73
4
avatar+327 

1.

Use the graph that shows the solution to f(x)=g(x) .

f(x)=1/x   (on side)−2

g(x)=x−2

 

What is the solution to f(x)=g(x) ?

Select each correct answer.

 

−1

1

2

3

 

2.

 

Use the graph that shows the solution to f(x)=g(x) .

What is the solution to f(x)=g(x) ?

 

x=−1

x = 0

x = 2

x = 3

 

3.

Use the graph that shows the solution to f(x)=g(x) .

What is the solution to f(x)=g(x) ?

Select each correct answer.

 

x = 0

x = 1

x = 2

x = 4

 

Thank you very much!!! Need help on these practice concepts because I am confused lol

 Feb 27, 2019
 #1
avatar+100546 
+2

First one

 

g(x)  is the same on both graphs

 

f(x) = 1/x - 2      is shown on the top graph   

 

So....the top graph is correct

 

The intersection points are  - 1  and 1

 

P.S. - If you allowed to......Desmos is a pretty good graphing utility that might help you

 

You can find it here :   https://www.desmos.com/calculator

 

 

cool cool cool

 Feb 27, 2019
 #4
avatar+327 
0

Thank you much! I will check out the desmos graphing system as well. It could come in handy for understanding problems like these!!

PhoenixForever  Feb 28, 2019
 #2
avatar+100546 
+2

Second one

 

If we put   0 into f(x), we get 2

Thus the point (0, 2)  is on the graph of f(x)

 

So....the first graph must be correct

 

The intersection point  is just  at   0

 

 

cool cool cool 

 Feb 27, 2019
 #3
avatar+100546 
+2

Last one

 

f(x) is the same  on both graphs

 

If we put 0 into 2^x  we get 2^(0)  = 1

 

So...the point (0, 1) is on the graph of  g(x)

 

So...again....the top graph is correct.....and the intersection points are at 0 and 2

 

cool cool cool

 Feb 27, 2019

8 Online Users

avatar