+0  
 
0
583
4
avatar+1832 

 

 

 

 

 

 Oct 19, 2014

Best Answer 

 #3
avatar+118609 
+10

Q16 is easy too

minimum travel time = $$\frac{1hr}{65miles}\times \frac{455miles}{1}=7hours$$

 

9.5-7=2.5hours

So you have less than 2.5 hours for lunch.

 Oct 19, 2014
 #1
avatar+118609 
+10

question 13

These are the motion in one direction formulas

You have initial and end velocities and distance and you want accel

You have u,v and s and you want a

no 4 is the only one that doesn't need time so use that one.

 

$$\\0=40^2+2*a*200\\
0=1600+400a\\
0=4+a\\
a=-4$$

Acceleeration    $$-4m/s^2$$

But you are just asked forthe magnitude - that is like absolute value - so the answer is 

 

$$4m/s^2$$

 

----------------------------------

 

 Oct 19, 2014
 #2
avatar+118609 
+10

14 is east

The cat goes 15m+10m=25m

in 20sec+8sec=28sec

average speed = 25/28=0.893m/s

 Oct 19, 2014
 #3
avatar+118609 
+10
Best Answer

Q16 is easy too

minimum travel time = $$\frac{1hr}{65miles}\times \frac{455miles}{1}=7hours$$

 

9.5-7=2.5hours

So you have less than 2.5 hours for lunch.

Melody Oct 19, 2014
 #4
avatar+1832 
0

very nice .. 

 

thank you melody 

 Oct 20, 2014

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