+118667 I just did a huge answer here and I have lost the lot! 
6! reads as 6 factorial
6!=1*2*3*4*5*6
34! / (34-6)! 6! = can be entered into any calculator but you will need to put the bottom in brackets
like this 34!/((34-6)!*6!)=
$${\frac{{\mathtt{34}}{!}}{\left((\left({\mathtt{34}}{\mathtt{\,-\,}}{\mathtt{6}}\right)){!}{\mathtt{\,\times\,}}{\mathtt{6}}{!}\right)}} = {\mathtt{1\,344\,904}}$$
I had writen a great deal more than this. If you would like more explanation or you need to know how to do it by hand, please ask and i will show you. 
+59 It cannot be understood what exactly you mean by "(34-6)! 6!", as you have not suggested an operator for combining the values "(34-6)!" and "6!". Therefore the equation currently cannot be solved.
+118667 I just did a huge answer here and I have lost the lot!
6! reads as 6 factorial
6!=1*2*3*4*5*6
34! / (34-6)! 6! = can be entered into any calculator but you will need to put the bottom in brackets
like this 34!/((34-6)!*6!)=
$${\frac{{\mathtt{34}}{!}}{\left((\left({\mathtt{34}}{\mathtt{\,-\,}}{\mathtt{6}}\right)){!}{\mathtt{\,\times\,}}{\mathtt{6}}{!}\right)}} = {\mathtt{1\,344\,904}}$$
I had writen a great deal more than this. If you would like more explanation or you need to know how to do it by hand, please ask and i will show you.
