36 less than or equal to 1-5z>-21. I need help solving this.

Thanks Chris,

This is what I would do with this question.

$$\\36 \le 1-5z>-21\\
$subtract 1 throughout$\\
35 \le -5z>-22\\
$divide throughout by -5 but you will have to turn the signs around$\\
-7 \ge z<-4.4\\
$now I will separate them because this really doesn't make much sense.$\\
-7\ge z \qquad and \qquad z<-4.4\\
z\le -7 \qquad and \qquad z<-4.4\\
so\\
Z\le -7$$

This original line  $$\\36 \le 1-5z>-21\\$$     IS NOT normal or good presentation.

It should have been presented as 

$$\\36 \le 1-5z \qquad and \qquad 1-5z >-21\\$$

36 ≤ 1 - 5z > -21     suubtract 1 from everything

35 ≤  -5z  > -22      divide everything by -5 and don't forget that we have to "reverse" the signs when dividing by a negative!!

-7 ≥ z < 22/5

Note that we must use the most restrictive interval, here .....  this is  ...   -7 ≥ z

ok so when u minus 1 what about the -5 and -22

I don't understand your question......

would you not add 5 to cancel the 5out and then add 5 to the -22 to make it -17

this whole problem is confusing me

No....remember.....it's -5z .....not just -5......  we need to subtract 1 in the middle at the start to get just -5z remaining.....

ok i got 35 less than or equal to -5z>-22 now what do i do