Rectangle ABCD is the base of pyramid PABCD. If AB = 8, BC = 4, $PA \perp AD$, $PA \perp AB$, and PB = 19, then what is the volume of PABCD?
+179 First of all, ABCD has area of 32.
Knowing that P is directly above A (from PA perpendicular to AD and AB), we use the Pythagorean Theorem on triangle PAB, getting PA = \(\sqrt297\).
With this, we have the volume of PABCD as \(\frac{32*\sqrt{297}}{3}\), or \(32\sqrt{33}\)
