A circular sheet of paper of radius 6 inches is cut into 4 equal sectors, and each sector is formed into a cone with no overlap. What is the height in inches of the cone?
+128474 The slant height of each cone = the radius of the original circle 6 in
The circumference of each cone at the base = Circumference of the circle / 4 = (2pi) (6) / 4 = 3 pi
C = 2pi r
3 pi = 2pi * r divide both sides by 2 pi
3/2 = r = 1.5 in
The height of each cone =
sqrt [ slant height ^2 - radius^2 ] =
sqrt [ ( 6)^2 - 1.5^2 ] = sqrt [ 36 - 2.25 ] ≈ 5.8 in
