Let A be the surface area of a 16 units by 1unit by 1 unit rright, rectangular prism and let B be the surface area of a 8 units by 2 units by 1 unit right rectangular prism. What is I A-B I in square units?

NoobGuest Jun 16, 2019

#1**+1 **

A=16

B=8

so

16+8=24 Caution I am not sure if I a supposed to do the stuff on the bottom so I would wait for a user just to make sure! Thanks for understanding. :)

But we start with A which is 16*1*1=16

then B which equals 8 so 8*2*1=16

16+16 = 32sq units

Nickolas Jun 16, 2019

#2**+3 **

A is the surface area of a 16 units by 1 unit by 1 unit right, rectangular prism.

In square units, A = 2(1)(1) + 2(1)(16) + 2(1)(16) = 2 + 32 + 32 = 66

B is the surface area of a 8 units by 2 units by 1 unit right, rectangular prism.

In square units, B = 2(1)(2) + 2(1)(8) + 2(2)(8) = 4+ 16 + 32 = 52

So....

| A - B | = | 66 square units - 52 square units | = 14 square units

hectictar Jun 16, 2019