4^(p-12)=8^5p what is p

4^(p-12)=8^(5p)         note that we can write 4 as 2^2 and we can write 8 as 2^3.......so we have

(2^2)^(p -  12)  = (2^3)^(5p)  

(2)^(2p - 24)  =  (2)^(15p)      and since the bases are the same, we can solve for the exponents

2p - 24  = 15p       rearrange

-13p = 24    divide both sides by -13

p  = -24/13