#1**+5 **

4^(p-12)=8^(5p) note that we can write 4 as 2^2 and we can write 8 as 2^3.......so we have

(2^2)^(p - 12) = (2^3)^(5p)

(2)^(2p - 24) = (2)^(15p) and since the bases are the same, we can solve for the exponents

2p - 24 = 15p rearrange

-13p = 24 divide both sides by -13

p = -24/13

CPhill
Jun 16, 2015

#1**+5 **

Best Answer

4^(p-12)=8^(5p) note that we can write 4 as 2^2 and we can write 8 as 2^3.......so we have

(2^2)^(p - 12) = (2^3)^(5p)

(2)^(2p - 24) = (2)^(15p) and since the bases are the same, we can solve for the exponents

2p - 24 = 15p rearrange

-13p = 24 divide both sides by -13

p = -24/13

CPhill
Jun 16, 2015