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4x^2 - 24x + 31 = 0 solve by completing the square?

A.) -3 + square root of 5/4, x=-3 - square root of 5/4

B.) x= 3 + square root of 5/4, x= 3 - square root of 5/4

C.) 1+ square root of 3/2, 1- square root of 3/2

D.) x= -1 +  square root of 3, -1 - square root of 3

 Feb 21, 2016
 #1
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Solve for x:
4 x^2-24 x+31 = 0

 

Divide both sides by 4:
x^2-6 x+31/4 = 0

 

Subtract 31/4 from both sides:
x^2-6 x = -31/4

 

Add 9 to both sides:
x^2-6 x+9 = 5/4

 

Write the left hand side as a square:
(x-3)^2 = 5/4

 

Take the square root of both sides:
x-3 = sqrt(5)/2 or x-3 = -sqrt(5)/2

 

Add 3 to both sides:
x = 3+sqrt(5)/2 or x-3 = -sqrt(5)/2

 

Add 3 to both sides:
Answer: | x = 3+sqrt(5)/2      or         x = 3-sqrt(5)/2

 Feb 21, 2016

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