Solve the following system:
{y/3-x/5 = -2 | (equation 1)
(5 x)/6-y/2 = -5 | (equation 2)
Swap equation 1 with equation 2:
{(5 x)/6-y/2 = -5 | (equation 1)
-x/5+y/3 = -2 | (equation 2)
Add 6/25 × (equation 1) to equation 2:
{(5 x)/6-y/2 = -5 | (equation 1)
0 x+(16 y)/75 = -16/5 | (equation 2)
Multiply equation 1 by 6:
{5 x-3 y = -30 | (equation 1)
0 x+(16 y)/75 = -16/5 | (equation 2)
Multiply equation 2 by 75/16:
{5 x-3 y = -30 | (equation 1)
0 x+y = -15 | (equation 2)
Add 3 × (equation 2) to equation 1:
{5 x+0 y = -75 | (equation 1)
0 x+y = -15 | (equation 2)
Divide equation 1 by 5:
{x+0 y = -15 | (equation 1)
0 x+y = -15 | (equation 2)
Collect results:
Answer: |x = -15 and y=-15
