I will take it from there.
$$4(x+2)=5x$$
Now, substitute the $$x$$, but I will start with 8.
$$4(x+2)=5x\Rightarrow4(8+2)=5(8)\Rightarrow4(10)=40\Rightarrow40=40\\\\\mbox{We\;can\;now\;see\;that\;the\;equation\;is\;true,\;so\;}x=40.$$
Let's substitute x into 8
x=8
now change everything into fractions
now, I don't get it. It has to be 2 4/8, bit 4/8. Can someone please help?
I think that the question is supposed to be
$$\\\frac{5}{x+2}=\frac{4}{x} \\\\
\frac{x+2}{5}=\frac{x}{4}\qquad \mbox{I turned both sides upside down}\\\\
\frac{20(x+2)}{5}=\frac{20x}{4}\qquad \mbox{I multiplied both sides by 20}\\\\
4(x+2)=5x\qquad \mbox{}\\\\$$
You should be able to do it from here.
I will take it from there.
$$4(x+2)=5x$$
Now, substitute the $$x$$, but I will start with 8.
$$4(x+2)=5x\Rightarrow4(8+2)=5(8)\Rightarrow4(10)=40\Rightarrow40=40\\\\\mbox{We\;can\;now\;see\;that\;the\;equation\;is\;true,\;so\;}x=40.$$
You have used a trial and error method to solve this. (Even though you only had one trial) Your answer is correct.
Try watching how other questions like this are solved and you will learn the high school method.
Some questions are just too difficult to use trial and error
You "trialled" x=8 and it worked.
You did not show us that you had "trialled" any other number .
Oh. I now get it. Even on the first post, I wrote out 8! Interesting...