$$5x-3=13-3x$$
Move the unknown numbers to one side and the known numbers to the other.
$$5x+3x=13+3$$
Add the two unknown numbers.
$$5x+3x=8x$$
Add the two known numbers.
$${\mathtt{13}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}} = {\mathtt{16}}$$
Divide the total of the known numbers using the unknown numbers.
$${\frac{{\mathtt{16}}}{{\mathtt{8}}}} = {\mathtt{2}}$$
And you're done!
To solve the problem, change $$x$$ into 2.
$$5x-3=13-3x\Rightarrow5*2-3=13-3*2$$
Now, multiply from both sides.
$$5*2=10$$
$$3*2=6$$
Now, combine the equation.
$$10-3=13-6$$
Now, subtract from both sides.
$$10-3=7$$
$$13-6=7$$
Now, compare both answers.
$$7=7$$
As we can see, the answer is correct.
So, the answer is $$\boxed{x=2}$$.
Hope that this helps!
$$5x-3=13-3x$$
Move the unknown numbers to one side and the known numbers to the other.
$$5x+3x=13+3$$
Add the two unknown numbers.
$$5x+3x=8x$$
Add the two known numbers.
$${\mathtt{13}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}} = {\mathtt{16}}$$
Divide the total of the known numbers using the unknown numbers.
$${\frac{{\mathtt{16}}}{{\mathtt{8}}}} = {\mathtt{2}}$$
And you're done!