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6 2/3 x 2 2/5 x 3 3/8 =

Guest Sep 2, 2014

Best Answer 

 #1
avatar+3450 
+5

First, turn these numbers into inproper fractions. Here's how we'd do that:

 

$$\begin{array}{l}
6\frac{2}{3} = \frac{6\times3+2}{3}=\frac{18+2}{3}=\frac{20}{3}\\\\
2\frac{2}{5} = \frac{2\times5+2}{5}=\frac{10+2}{5}=\frac{12}{5}\\\\
3\frac{3}{8} = \frac{3\times8+3}{8}=\frac{24+3}{8}=\frac{27}{8}
\end{array}$$

 

Now we get:

 

$$\frac{20}{3}\times\frac{12}{5}\times\frac{27}{8}$$

 

This can simplified, so we get:

 

$$\frac{1}{1}\times\frac{2}{1}\times\frac{27}{1}$$

 

$$\frac{1\times2\times27}{1\times1\times1}$$

 

$$\frac{54}{1}$$

 

$$54$$

NinjaDevo  Sep 3, 2014
 #1
avatar+3450 
+5
Best Answer

First, turn these numbers into inproper fractions. Here's how we'd do that:

 

$$\begin{array}{l}
6\frac{2}{3} = \frac{6\times3+2}{3}=\frac{18+2}{3}=\frac{20}{3}\\\\
2\frac{2}{5} = \frac{2\times5+2}{5}=\frac{10+2}{5}=\frac{12}{5}\\\\
3\frac{3}{8} = \frac{3\times8+3}{8}=\frac{24+3}{8}=\frac{27}{8}
\end{array}$$

 

Now we get:

 

$$\frac{20}{3}\times\frac{12}{5}\times\frac{27}{8}$$

 

This can simplified, so we get:

 

$$\frac{1}{1}\times\frac{2}{1}\times\frac{27}{1}$$

 

$$\frac{1\times2\times27}{1\times1\times1}$$

 

$$\frac{54}{1}$$

 

$$54$$

NinjaDevo  Sep 3, 2014

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