Integer solutions are x = + or - 1
I would not have thought to do that.
How can you tell that there will be another solution as as $$x\rightarrow -\infty$$ ?
Because, if you look at the original form of the equation, 4-∞ = 0, 6-∞ = 0 and 9-∞ = 0 i.e. each of the terms on the LHS is individually zero.
In that limit my rearranged version of the equation doesn't hold, because a divide by zero would be involved.