6y^2-60y+126
y^2-6y-7
simplify please
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Here's the first one.....first, take out the common factor, 6,......so we have
6 [ (y2 - 10y + 21) ]
Now, we need to factor inside the brackets. We're looking for two numbers that multiply to 21 and sum to -10.
The first two things I think of are (-7) and (-3). I think those will work. So we have...
6(y - 7)(y - 3)
For the second one, we're looking for two numbers that multiply to -7 and sum to -6. (-1) and (+7) multiply to -7, but their sum is 6. Let's just change the signs. (+1) and (-7) multiply to -7 and sum to -6. Looks like those are what we need. So we have...
(y + 1)(y - 7)
$$\frac{6y^2-60y+126}{y^2-6y-7}\\\\
\frac{6(y^2-10y+21)}{(y-7)(y+1)}\\\\
\frac{6(y-3)(y-7)}{(y-7)(y+1)}\\\\
\frac{6(y-3)}{y+1}\\\\$$
6y^2-60y+126
y^2-6y-7
simplify please
--------------------------------------------------------------------------------------------------------------------------
Here's the first one.....first, take out the common factor, 6,......so we have
6 [ (y2 - 10y + 21) ]
Now, we need to factor inside the brackets. We're looking for two numbers that multiply to 21 and sum to -10.
The first two things I think of are (-7) and (-3). I think those will work. So we have...
6(y - 7)(y - 3)
For the second one, we're looking for two numbers that multiply to -7 and sum to -6. (-1) and (+7) multiply to -7, but their sum is 6. Let's just change the signs. (+1) and (-7) multiply to -7 and sum to -6. Looks like those are what we need. So we have...
(y + 1)(y - 7)
Hi Chris,
The web address contained the actual question - I guess that is why my answer seemed a bit strange to you.