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-7(2x + 1) + 3(5x – 4) = 0

 Dec 12, 2014

Best Answer 

 #2
avatar+752 
+5

$${\mathtt{\,-\,}}{\mathtt{7}}{\mathtt{\,\times\,}}\left({\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{3}}{\mathtt{\,\times\,}}\left({\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{4}}\right) = {\mathtt{0}}$$

$${\mathtt{\,-\,}}{\mathtt{14}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{7}}{\mathtt{\,\small\textbf+\,}}{\mathtt{15}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{12}} = {\mathtt{0}}$$

$${\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{19}} = {\mathtt{0}}$$

$${\mathtt{x}} = {\mathtt{19}}$$

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 Dec 12, 2014
 #1
avatar+23252 
+5

-7(2x + 1) + 3(5x - 4)  =  0

Use the Distributive Property:  -7(2x) + (-7)(1) + 3(5x) + 3(-4)  =  0

Multiply:                                                  -14x - 7 + 15x - 12  =  0

Simplify:                                                                     x - 19  =  0

Add 21 to both sides:                                                          x  =  19

 Dec 12, 2014
 #2
avatar+752 
+5
Best Answer

$${\mathtt{\,-\,}}{\mathtt{7}}{\mathtt{\,\times\,}}\left({\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{3}}{\mathtt{\,\times\,}}\left({\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{4}}\right) = {\mathtt{0}}$$

$${\mathtt{\,-\,}}{\mathtt{14}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{7}}{\mathtt{\,\small\textbf+\,}}{\mathtt{15}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{12}} = {\mathtt{0}}$$

$${\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{19}} = {\mathtt{0}}$$

$${\mathtt{x}} = {\mathtt{19}}$$

Sasini Dec 12, 2014

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