#4**+5 **

think about this

$${\mathtt{\,-\,}}{\frac{{\mathtt{9}}}{{\mathtt{0.1}}}} = -{\mathtt{90}}$$

$${\mathtt{\,-\,}}{\frac{{\mathtt{9}}}{{\mathtt{0.01}}}} = -{\mathtt{900}}$$

$${\mathtt{\,-\,}}{\frac{{\mathtt{9}}}{{\mathtt{0.001}}}} = -{\mathtt{9\,000}}$$

$$\frac{-9}{n}\quad \mbox{ approaches} -\infty \mbox{ as n }\rightarrow\: ^+0$$

BUT n can approach 0 from above or below.

$${\mathtt{\,-\,}}{\frac{{\mathtt{9}}}{-{\mathtt{0.1}}}} = {\mathtt{90}}$$

$${\mathtt{\,-\,}}{\frac{{\mathtt{9}}}{-{\mathtt{0.01}}}} = {\mathtt{900}}$$

$${\mathtt{\,-\,}}{\frac{{\mathtt{9}}}{-{\mathtt{0.001}}}} = {\mathtt{9\,000}}$$

This time

$$\frac{-9}{n}\quad \mbox{ approaches} +\infty \mbox{ as n }\rightarrow\: ^-0$$

n cannot approach -infinity and +infinity at the same time and end up at the same place so -9/0 must be **undefined**. I think **indeterminant** is the more common term these days but to the best of my understanding both terms mean the same thing.

Does that make sense to you?

Melody Jun 12, 2014

#1**0 **

-9/0

-9/1 ÷ 0/0

-9/1 * 0/0

-0/0

= 0

I'm not entirely sure if this is correct because I tried it on two different calculators. One said ERROR and the other one said -Infinity.

...?

NinjaDevo Jun 11, 2014

#3**+5 **

Any number divided by 0 (zero) is undefined. This includes 0/0.

It is NOT infinity nor negative infinity.

The calculator that returned "-Infinity" is wrong!

Guest Jun 12, 2014

#4**+5 **

Best Answer

think about this

$${\mathtt{\,-\,}}{\frac{{\mathtt{9}}}{{\mathtt{0.1}}}} = -{\mathtt{90}}$$

$${\mathtt{\,-\,}}{\frac{{\mathtt{9}}}{{\mathtt{0.01}}}} = -{\mathtt{900}}$$

$${\mathtt{\,-\,}}{\frac{{\mathtt{9}}}{{\mathtt{0.001}}}} = -{\mathtt{9\,000}}$$

$$\frac{-9}{n}\quad \mbox{ approaches} -\infty \mbox{ as n }\rightarrow\: ^+0$$

BUT n can approach 0 from above or below.

$${\mathtt{\,-\,}}{\frac{{\mathtt{9}}}{-{\mathtt{0.1}}}} = {\mathtt{90}}$$

$${\mathtt{\,-\,}}{\frac{{\mathtt{9}}}{-{\mathtt{0.01}}}} = {\mathtt{900}}$$

$${\mathtt{\,-\,}}{\frac{{\mathtt{9}}}{-{\mathtt{0.001}}}} = {\mathtt{9\,000}}$$

This time

$$\frac{-9}{n}\quad \mbox{ approaches} +\infty \mbox{ as n }\rightarrow\: ^-0$$

n cannot approach -infinity and +infinity at the same time and end up at the same place so -9/0 must be **undefined**. I think **indeterminant** is the more common term these days but to the best of my understanding both terms mean the same thing.

Does that make sense to you?

Melody Jun 12, 2014

#5**0 **

Ooooops I must be confusing with this $$\lim\limits_{x \to 0}{\frac{c}{x}} = \infty$$ $$c = const$$. Really sorry, I'm just hooked on maths analysis recently.

scrutinizer Jun 12, 2014