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∫ 9 (3𝑥 + 10) 6

 Jan 12, 2021
 #1
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Is this your integral?

 

9(3x+10)6dx

 

If so....

 

Let's pick   u = 3x + 10   which means  du = 3 dx   and then substitute these in like this:

 

=9(3x+10)6dx =33(3x+10)6dx =3(3x+10)63dx =3u6du =3u6du

                                           Now we can use the rule which says  undu = un+1n+1+c    to get...

=3u77+c =37u7+c

                                           Now let's substitute  3x + 10  back in for  u

=37(3x+10)7+c

 Jan 12, 2021

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