+2446 #10, why not?
According to the original relation, f(x)=3√x−4. There are a few steps that need to be done in order to find the inverse.
#1) Convert to y=-notation. I find that it is easier when working with this notation. This is quite a simple step, wouldn't you agree?
f(x)=3√x−4⇒y=3√x−4
#2) Now, replace all instances of a "y" with an "x," and replace all instances of an "x" with a "y." This is not a difficult step, either, as you might imagine.
y=3√x−4⇒x=3√y−4
#3) Solve for y. This step can range in difficulty. In this case, it is quite a simple step.
| x=3√y−4 | Cube both sides. |
| x3=y−4 | Add 4 to both sides to isolate y. |
| y=x3+4 | |
#4) Convert back to function notation since the original problem was given in function notation. This is quite simple, too.
y=x3+4⇒f−1(x)=x3+4
#5) Correspond your answer with the answer choices given!
+2446 #10, why not?
According to the original relation, f(x)=3√x−4. There are a few steps that need to be done in order to find the inverse.
#1) Convert to y=-notation. I find that it is easier when working with this notation. This is quite a simple step, wouldn't you agree?
f(x)=3√x−4⇒y=3√x−4
#2) Now, replace all instances of a "y" with an "x," and replace all instances of an "x" with a "y." This is not a difficult step, either, as you might imagine.
y=3√x−4⇒x=3√y−4
#3) Solve for y. This step can range in difficulty. In this case, it is quite a simple step.
| x=3√y−4 | Cube both sides. |
| x3=y−4 | Add 4 to both sides to isolate y. |
| y=x3+4 | |
#4) Convert back to function notation since the original problem was given in function notation. This is quite simple, too.
y=x3+4⇒f−1(x)=x3+4
#5) Correspond your answer with the answer choices given!
Help.
