+0  
 
0
1728
4
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9 to the 4th power over 9 to the 6th power

 Dec 17, 2014

Best Answer 

 #4
avatar+26393 
+5

9 to the 4th power over 9 to the 6th power

$$\small{\text{
Set $ 9^4 = \dfrac{ 1 }{ 9^{-4} } $. We have
$
\dfrac{ 9^4 }{ 9^6 } = \dfrac{1 }{ 9^6 }*9^4 = \dfrac{1 }{ 9^6 }*\dfrac{ 1 }{ 9^{-4} } = \dfrac{1 }{ 9^{6-4} } = \dfrac{1 }{ 9^{2} } = \dfrac{1}{81} = 0.01234567901
$
}}$$

 Dec 17, 2014
 #1
avatar+70 
0

0. 6666666666666667

 Dec 17, 2014
 #2
avatar+23252 
+5

94 / 96  =  9-2       (when dividing numbers with the same base, subtract exponents)

9-2  =  1/92  =  1/81  =  0.012345679012...

Or:  94 / 96  =  6561/531441  =  1/81  =   0.012345679012...

 Dec 17, 2014
 #3
avatar
+5

You need to simplify the answer and then solve. When dividing by like numbers (I'm not sure whether of not they have to be alike but I'm pretty sure it doesn't matter in this particular problem), you can subtract the exponents. Because you're subtracting 6 from 4, you're going to get a negative number for an exponent: -2. Then, you make the -2 a positive 2 by turning it into a fraction, so it'll be 1 over 9 to the second power. You'll get 1 over 81. That's your answer in fraction form.

 Dec 17, 2014
 #4
avatar+26393 
+5
Best Answer

9 to the 4th power over 9 to the 6th power

$$\small{\text{
Set $ 9^4 = \dfrac{ 1 }{ 9^{-4} } $. We have
$
\dfrac{ 9^4 }{ 9^6 } = \dfrac{1 }{ 9^6 }*9^4 = \dfrac{1 }{ 9^6 }*\dfrac{ 1 }{ 9^{-4} } = \dfrac{1 }{ 9^{6-4} } = \dfrac{1 }{ 9^{2} } = \dfrac{1}{81} = 0.01234567901
$
}}$$

heureka Dec 17, 2014

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