+1995 A 10.0 Ω resistor is in parallel with a 20.0 Ω resistor and supplied by a 9.0 V battery. What is the current passing through the 20.0 Ω resistor?
0.90 A
0.45 A
6.00 A
1.35 A
i think its B, however im not sure?please explain the equation ? thank you
+37146 Again....the resistors are wired in PARALLEL ....so they BOTH have 20v applied across them
v/r = i 9v / 20 ohm =.......A
+1995 the answer actually ended up being B , hmm im not sure then. Maybe im not understanding this as much as i thought
+37146 As an exercise let's find the current through the 10 ohm resistor
9v/10 ohm = .9 A
so the total current is thus .45 + .9 = 1.35 A
the resultant resistance is thus 9 v/ 1.35 A = R = 6 .667 ohm
Is this true?
Calculate the resultant resistance of the two resistors in parallel 1/ (1/10 + 1/20) = 6.667 ohm ! TRUE !
