+0  
 
0
65
4
avatar+1898 

A 10.0 Ω resistor is in parallel with a 20.0 Ω resistor and supplied by a 9.0 V battery. What is the current passing through the 20.0 Ω resistor?

0.90 A

0.45 A

6.00 A

1.35 A

 

i think its B, however im not sure?please explain the equation ? thank you

 Apr 15, 2020
edited by jjennylove  Apr 15, 2020
 #1
avatar+23689 
+1

Again....the resistors are wired in PARALLEL ....so they BOTH have 20v applied across them

 

v/r = i      9v  / 20 ohm =.......A

 Apr 15, 2020
 #2
avatar+1898 
+1

the answer actually ended up being B , hmm im not sure then. Maybe im not understanding this as much as i thought

jjennylove  Apr 15, 2020
 #3
avatar+23689 
+1

  As an exercise    let's find the current through the 10 ohm resistor

 

9v/10 ohm  =   .9 A  

 

so the total current is thus  .45 + .9 = 1.35 A

 

the resultant resistance is thus    9 v/ 1.35 A = R = 6 .667 ohm

 

Is this true?

     Calculate the resultant resistance of the two resistors in parallel     1/ (1/10 + 1/20)  =  6.667   ohm  !    TRUE !

ElectricPavlov  Apr 15, 2020
 #4
avatar+23689 
+1

Yes. it is B

ElectricPavlov  Apr 15, 2020

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