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# A 47-foot-long piece of pipe is to be cut into three pieces. The second piece is three times as long as the first piece, and the third piece

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A 47-foot-long piece of pipe is to be cut into three pieces. The second piece is three times as long as the first piece, and the third piece is two feet more than five times the length of the first piece. What is the length of the longest piece?

Jul 3, 2014

#1
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There are 3 pieces: The second piece is three times as long as the first piece, and the third piece is two feet more than five times the length of the first piece.

So if x = the length of the first piece, the total length would equal: x + 3x + (5x + 2)

First set up the equation:

47 = x + 3x + 5x + 2

Simplify:

47 = 9x + 2

Subtract 2:

45 = 9x

Divide by 9:

x = 5

So now you know the length of the first piece is 5 feet. The longest piece will be "two feet more than five times the length of the first piece" so it is : 2 + 5 * 5

= 2 + 25

= 27 feet long.

Jul 3, 2014

#1
+5454
+31

There are 3 pieces: The second piece is three times as long as the first piece, and the third piece is two feet more than five times the length of the first piece.

So if x = the length of the first piece, the total length would equal: x + 3x + (5x + 2)

First set up the equation:

47 = x + 3x + 5x + 2

Simplify:

47 = 9x + 2

Subtract 2:

45 = 9x

Divide by 9:

x = 5

So now you know the length of the first piece is 5 feet. The longest piece will be "two feet more than five times the length of the first piece" so it is : 2 + 5 * 5

= 2 + 25

= 27 feet long.

kitty<3 Jul 3, 2014