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A 52N sled is pushed across a cement sidewalk at a constant speed. A horizontal force of 36N is exerted. What is the coefficient of sliding friction between the sidewalk and the metal runners of the sled?

physics
Guest Oct 5, 2014

Best Answer 

 #1
avatar+26402 
+10

At constant speed the net force on the sled is zero (Newton's 1st law of motion).  The frictional force is given by μ*weight where μ is the coefficient of friction.

 

μ*52 = 36

μ = 36/52

μ ≈ 0.692

Alan  Oct 6, 2014
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1+0 Answers

 #1
avatar+26402 
+10
Best Answer

At constant speed the net force on the sled is zero (Newton's 1st law of motion).  The frictional force is given by μ*weight where μ is the coefficient of friction.

 

μ*52 = 36

μ = 36/52

μ ≈ 0.692

Alan  Oct 6, 2014

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