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If a ball is thrown straight up into the air with an initial velocity of 55 ft/s, it height in feet after t second is given by y=55t−16t2. Find the average velocity for the time period begining when t=2 and lasting

 

(i) 0.1 Seconds:

(ii) 0.01 Seconds:

(iii) 0.001 Seconds:

 

Finally based on the above results, guess what the instantaneous velocity of the ball is when t=2

 Jan 25, 2016
edited by Guest  Jan 25, 2016
edited by Guest  Jan 25, 2016
edited by Guest  Jan 25, 2016
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(original poster)

The answer I got for the first one is 21.4, second is 22.84, and third is 22.984..

 

these appear to be incorrect.. :\

 Jan 25, 2016

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