ماهوة ناتج a block of 180kg supported by a cylindrical wire of lenghtt 3m and cross sectional area of radius 0.005m the wire is stretched by 25*0.0001m the tensile stress
+33657 Stress is force per unit cross-sectional area: = (180kg*9.81m/s2)/(pi*0.0052m2)
$${\frac{{\mathtt{180}}{\mathtt{\,\times\,}}{\mathtt{9.81}}}{\left({\mathtt{\pi}}{\mathtt{\,\times\,}}{{\mathtt{0.005}}}^{{\mathtt{2}}}\right)}} = {\mathtt{22\,482\,863.880\: \!933\: \!502\: \!712\: \!055\: \!6}}$$
Stress ≈ 22482864 N/m2 or Stress ≈ 22.48 MPa
You give the original length and the extension, so if you want the Strain as well:
Strain = extension/original length = 0.0025/3 = 8.3*10-4
.
+33657 Stress is force per unit cross-sectional area: = (180kg*9.81m/s2)/(pi*0.0052m2)
$${\frac{{\mathtt{180}}{\mathtt{\,\times\,}}{\mathtt{9.81}}}{\left({\mathtt{\pi}}{\mathtt{\,\times\,}}{{\mathtt{0.005}}}^{{\mathtt{2}}}\right)}} = {\mathtt{22\,482\,863.880\: \!933\: \!502\: \!712\: \!055\: \!6}}$$
Stress ≈ 22482864 N/m2 or Stress ≈ 22.48 MPa
You give the original length and the extension, so if you want the Strain as well:
Strain = extension/original length = 0.0025/3 = 8.3*10-4
.
