A box has a total surface area of The length of the box is equal to twice its width, as well as equal to less than its height. What is the height of the box?
Did you directly copy it from somewhere else without proofreading over it?
Please do not, because the LaTeX may mess up.
Let length = L, width = W, height = H.
\(2(LW + WH + HL) = 100\\ L = 2W\\ L = H - 3\)
Changing the subjects of the second and third equations,
\(W = \dfrac L2\\ H = 3 + L\)
Substituting these into the first equation:
\(2\left(L \cdot \dfrac L2 + \dfrac L2 \cdot (3 + L) + (3 + L) \cdot L \right) = 100\\ L^2 + 3L(3 + L) = 100\\ 4L^2 + 9L - 100 = 0\)
Solving by quadratic formula gives \(L = 4\)
I believe you can work out the width and the height from here.