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# A bullet train left for japan at 0700. the trian stopped over at malaysia for half an hour before continuing its journey to japan . it reach

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A bullet train left for japan at 0700. the trian stopped over at malaysia for half an hour before continuing its journey to japan . it reach japan at 1345. if the average speed of the train was 350km/h , what was the total distance covered by the train

Jul 10, 2015

#1
+101733
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I  think everyone drowned and the train derailed somewhere in the East China Sea

I suppose it was an amphibious train

It took 6hours and 45 minutes.  Take out the 30 min break.

That is 6 hours and 15 minutes.

That is      $$6\frac{1}{4}\;\;hours = 6.25\; hours$$

$$6.25hours\times 350km/hour$$

$${\mathtt{6.25}}{\mathtt{\,\times\,}}{\mathtt{350}} = {\frac{{\mathtt{4\,375}}}{{\mathtt{2}}}} = {\mathtt{2\,187.5}}$$

2187.5 km

Jul 10, 2015

#1
+101733
+8

I  think everyone drowned and the train derailed somewhere in the East China Sea

I suppose it was an amphibious train

It took 6hours and 45 minutes.  Take out the 30 min break.

That is 6 hours and 15 minutes.

That is      $$6\frac{1}{4}\;\;hours = 6.25\; hours$$

$$6.25hours\times 350km/hour$$

$${\mathtt{6.25}}{\mathtt{\,\times\,}}{\mathtt{350}} = {\frac{{\mathtt{4\,375}}}{{\mathtt{2}}}} = {\mathtt{2\,187.5}}$$

2187.5 km

Melody Jul 10, 2015