Nevermind, I think I got it.

Question

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A climber is standing at the top of Mount Kazbek, approximately 3.1 mi above sea level. The radius of the Earth is 3959 mi.

What is the climber's distance to the horizon?

Enter your answer as a decimal. Round only your final answer to the nearest tenth.

Answer: 156.7 mi.

edited by Gwendolynkristine Jun 1, 2017

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Best Answer

We have a right triangle.....

One leg is the radius of the Earth..... and the hypotenuse = Earth's radius + 3.1 miles

The distance to the horizon forms the other leg and is given by

sqrt [ ( 3959 + 3.1)^2 - 3959^2 ] ≈ 156.7 miles

CPhill Jun 1, 2017

CPhill · Answer 1 · 2017-06-01T03:49:38

We have a right triangle.....

One leg is the radius of the Earth..... and the hypotenuse = Earth's radius + 3.1 miles

The distance to the horizon forms the other leg and is given by

sqrt [ ( 3959 + 3.1)^2 - 3959^2 ] ≈ 156.7 miles

CPhill · Answer 2 · 2017-06-01T04:09:24

Good job, Gwendolyn....!!!!