A dart is thrown at the square target shown. Assuming the dart hits the target at a random location, what is the probability that it will be

I have a little different answer than Melody......see the following pic.....{I'm assuming the small square is 2 inches on each side....I''m also assuming that the distances between the squares are measured from edge to edge}

The area between the  medium square and the small square {the shaded area}  = 8^2 - 2^2  = 64 - 4 = 60 square units 

And the area of the whole dartboard = 16^2  = 256

So....the probability that the dart lands in the shaded area between the small and medium square = 60/256  = 15/64

hi Mellie,

since when is a dart board square?

Anyway the area of the whole board is 4*4=16 cm squared.   That will be the denominator.

the shaded area will be  3*3-2*2 = 9-4 = 5 cm squared.

So the prob that it will be in the sahaded region is     $${\frac{{\mathtt{5}}}{{\mathtt{16}}}}$$

Yes I misread the question.  sorry.

Thanks Chris :))

Actually, Melody was correct, but still thank you so much for helping me!!

$$The total area of the dartboard is $4\times4=16$ square inches. The area of the shaded region is the area of the $3\times3$ region after subtracting the area of the $2\times2$ region, or $9-4=5$ square inches. The shaded region is $5$ square inches out of the possible $16$ square inches the dart could hit, so the probability of the dart hitting the shaded region is $\boxed{\frac{5}{16}}$.$$

No Mellie,

Chris answered this one correctly mine is not correct.    

(Unless perhaps you were given a pic to help eliminate confusion :/  )

Your resorces often seem to give you incorrect answers :)

Or at least they often give you the correct answer to a slightly different question from the one that they actually asked.