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A fair 6-sided die is rolled. If I roll $n$, then I win $n^2$ dollars. What is the expected value of my win? Express your answer as a dollar value rounded to the nearest cent.

Mellie  Apr 25, 2015

Best Answer 

 #1
avatar+27228 
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Expected win = (1/6)*(1^2 + 2^2 + 3^2 + 4^2 + 5^2 + 6^2) = 15.167

 

or $15.17 to the nearest cent. 

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Alan  Apr 25, 2015
 #1
avatar+27228 
+11
Best Answer

Expected win = (1/6)*(1^2 + 2^2 + 3^2 + 4^2 + 5^2 + 6^2) = 15.167

 

or $15.17 to the nearest cent. 

.

Alan  Apr 25, 2015

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