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0
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This identity, when calculated correctly, is a very familiar constant. The question is this: how many accurate digits are there in its decimal expansion?
Ln{[640,320^3 + 744]^2 - 393,768} / sqrt(652)=?

 Feb 3, 2016

Best Answer 

 #5
avatar+26388 
+35

This identity, when calculated correctly, is a very familiar constant. The question is this: how many accurate digits are there in its decimal expansion? {nl} Ln{[640,320^3 + 744]^2 - 393,768} / sqrt(652)=?

 

"\(\dots\) one example on Mathworld's Pi Approximations page.

The same formula from Ramanujan that I have used was extended in a different way by Warda (2004) with the result:

π   ≈  ln [ ( 6403203 + 744 )2 - 2 · 196884 ] / ( 2 · \(\sqrt{163}\) )    [ Heureka: \(\pi \approx \frac{ \ln{ [~ ( 640320^3 + 744 )^2 - 2 \cdot 196884 ~]} } { 2 \cdot \sqrt{163}} \) ]

giving the resulting approximation to π :

π   ≈ 3.1415926535897932384626433832795028841971693992820...

that is accurate to 46 digits past the decimal point \(\dots \)".

( From http://members.bex.net/jtcullen515/math7.htm )

 

see: http://members.bex.net/jtcullen515/math7.htm

and see: http://mathworld.wolfram.com/PiApproximations.html

 

laugh

 Feb 3, 2016
edited by heureka  Feb 3, 2016
edited by heureka  Feb 3, 2016
edited by heureka  Feb 3, 2016
 #1
avatar+129850 
+5

This evaluates to "pi"

 

Since this an irrational number, it is never precisely "accurate".....however....we can make it as "accurate" as we want to a specified number of digits......

 

 

cool cool cool

 Feb 3, 2016
 #2
avatar
+5

Thank you CPhill: How many accurate decimal digits can you get? What I mean is this: 355/113=3.141592920.......gives you 6 accurate decimal digits, so with that expression, how many accurate decimal digits can you get out of it?

 Feb 3, 2016
 #3
avatar+129850 
+10

Oh....I see what you mean.....!!!

 

Here are the 1st 100 digits of pi :

 

3.[141592653589793238462643383279502884197169399]37510582097494459

23078164062862089986280348253421170679

 

 

Here is the result of your expression as given by WolframAlpha :

 

3.[141592653589793238462643383279502884197169399]2820711147894514138

916383017070856233260338755405432911712444501586...

 

So...it looks as though your expression is accurate  up to 45 decimal digits  [if i counted correctly.....!!!]

 

 

cool cool cool

 Feb 3, 2016
edited by CPhill  Feb 3, 2016
edited by CPhill  Feb 3, 2016
 #4
avatar
+5

This expression gives:

3.1415926535 8979323846 2643383279 5028841971 69399 28207 1114789451 4138916383 0

Pi is:

3.1415926535 8979323846 2643383279 5028841971 69399 37510 5820974944 5923078164 

So, by simple counting, the expression in question gives 45 accurate decimal digits of Pi.

 Feb 3, 2016
 #5
avatar+26388 
+35
Best Answer

This identity, when calculated correctly, is a very familiar constant. The question is this: how many accurate digits are there in its decimal expansion? {nl} Ln{[640,320^3 + 744]^2 - 393,768} / sqrt(652)=?

 

"\(\dots\) one example on Mathworld's Pi Approximations page.

The same formula from Ramanujan that I have used was extended in a different way by Warda (2004) with the result:

π   ≈  ln [ ( 6403203 + 744 )2 - 2 · 196884 ] / ( 2 · \(\sqrt{163}\) )    [ Heureka: \(\pi \approx \frac{ \ln{ [~ ( 640320^3 + 744 )^2 - 2 \cdot 196884 ~]} } { 2 \cdot \sqrt{163}} \) ]

giving the resulting approximation to π :

π   ≈ 3.1415926535897932384626433832795028841971693992820...

that is accurate to 46 digits past the decimal point \(\dots \)".

( From http://members.bex.net/jtcullen515/math7.htm )

 

see: http://members.bex.net/jtcullen515/math7.htm

and see: http://mathworld.wolfram.com/PiApproximations.html

 

laugh

heureka Feb 3, 2016
edited by heureka  Feb 3, 2016
edited by heureka  Feb 3, 2016
edited by heureka  Feb 3, 2016

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