+10 A girl is half the age of her mother. Mother is 5yrs less than father and the sum of the 3 ages is 100 find each age
+349 x = girl's age
2x = mom's age
2x + 5 = father's age
\(x + 2x+2x+5=100\)
\(5x+5=100\)
\(5x=95\)
\(x = 19\)
The girl's age is 19, the mother's age is 19*2 or 38, and the father's age is 38+5 or 43.
CHECK: 19 + 38 + 43 = 100?
100 = 100
+349 x = girl's age
2x = mom's age
2x + 5 = father's age
\(x + 2x+2x+5=100\)
\(5x+5=100\)
\(5x=95\)
\(x = 19\)
The girl's age is 19, the mother's age is 19*2 or 38, and the father's age is 38+5 or 43.
CHECK: 19 + 38 + 43 = 100?
100 = 100
