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A girl was eight years old on her first birthday. How could that be?

Guest May 4, 2015

Best Answer 

 #1
avatar+78577 
+18

 

 

If she was born on Feb 29th in a year that was 4 years before a century whose first two digits are not evenly divisible by 4.

For example.....if she was born on Feb 29th, 1896.....4 years later will not be a leap year because 1900 has its first two digits = 19.....and this is not evenly divisible by 4.

So...her "first" birthday will be on Feb 29th, 1904......eight years after she was born  !!!!!!!

 

  

CPhill  May 4, 2015
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2+0 Answers

 #1
avatar+78577 
+18
Best Answer

 

 

If she was born on Feb 29th in a year that was 4 years before a century whose first two digits are not evenly divisible by 4.

For example.....if she was born on Feb 29th, 1896.....4 years later will not be a leap year because 1900 has its first two digits = 19.....and this is not evenly divisible by 4.

So...her "first" birthday will be on Feb 29th, 1904......eight years after she was born  !!!!!!!

 

  

CPhill  May 4, 2015
 #2
avatar+90988 
+5

I didn't know that Chris.

If the first 2 digits if a new century are not divisable by 4 then it will not be a leap year.

Cool!  Thanks.     

Melody  May 5, 2015

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