The 2000 kg truck rolls down hill reaching a speed of 30 m/s just before hitting a tree. The vehicle stops 0.72 seconds after first making contact with the tree. What is the average force applied by the tree?

Please can someone check this.

I do not know so I am going to guess. :)

F=mass* acceleration m=2000kg

v=0, u=30m/s, t=0.72sec, a=?

v=u+at

0=30+a*0.72

-30/0.72=a

a=-41.6 repeater m/s^2

F=2000*41.66666

F=83333 kgm/s^2 = 83,333 Newtons (to the nearest Newton)