The 2000 kg truck rolls down hill reaching a speed of 30 m/s just before hitting a tree. The vehicle stops 0.72 seconds after first making contact with the tree. What is the average force applied by the tree?
Please can someone check this.
I do not know so I am going to guess. :)
F=mass* acceleration m=2000kg
v=0, u=30m/s, t=0.72sec, a=?
v=u+at
0=30+a*0.72
-30/0.72=a
a=-41.6 repeater m/s^2
F=2000*41.66666
F=83333 kgm/s^2 = 83,333 Newtons (to the nearest Newton)
