We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website.
Please click on "Accept cookies" if you agree to the setting of cookies. Cookies that do not require consent remain unaffected by this, see
cookie policy and privacy policy.
DECLINE COOKIES

A minor league baseball team plays 96 games in a season. If the team won 15

more than twice as many games as they lost, how many wins and losses did the team have?

How many games did the team lose?

How many games did the team win?

ladiikeiii Oct 20, 2017

#1**+2 **

Let's call the number of wins " W ", and the number of losses " L ".

There are 96 games altogether, so.... W + L = 96

The number of wins is 15 more than twice the number of losses, so.... W = 15 + 2L

W + L = 96

We can substitute 15 + 2L in for W since W = 15 + 2L .

15 + 2L + L = 96

Subtract 15 from both sides.

2L + L = 96 - 15

Combine like terms.

3L = 81

Divide both sides by 3 .

L = 27

They lost 27 of the games.

Remember, there are 96 games total... W + L = 96 → W = 96 - L = 96 - 27 = 69

They won 69 of the games.

hectictar Oct 20, 2017

#1**+2 **

Best Answer

Let's call the number of wins " W ", and the number of losses " L ".

There are 96 games altogether, so.... W + L = 96

The number of wins is 15 more than twice the number of losses, so.... W = 15 + 2L

W + L = 96

We can substitute 15 + 2L in for W since W = 15 + 2L .

15 + 2L + L = 96

Subtract 15 from both sides.

2L + L = 96 - 15

Combine like terms.

3L = 81

Divide both sides by 3 .

L = 27

They lost 27 of the games.

Remember, there are 96 games total... W + L = 96 → W = 96 - L = 96 - 27 = 69

They won 69 of the games.

hectictar Oct 20, 2017