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A minor league baseball team plays 96 games in a season. If the team won 15

more than twice as many games as they lost, how many wins and losses did the team have?

 

How many games did the team lose?

How many games did the team​ win?

ladiikeiii  Oct 20, 2017

Best Answer 

 #1
avatar+5227 
+2

Let's call the number of wins  " W ", and the number of losses  " L ".

 

There are  96  games altogether, so....       W + L  =  96

 

The number of wins is 15 more than twice the number of losses, so....     W  =  15 + 2L

 

W + L  =  96

                                      We can substitute  15 + 2L  in for  W  since  W  =  15 + 2L .

15 + 2L + L  =  96

                                      Subtract  15  from both sides.

2L + L  =  96 - 15

                                      Combine like terms.

3L  =  81

                                      Divide both sides by  3 .

L  =  27

 

They lost  27  of the games.

 

Remember, there are 96 games total...   W + L  =  96   →  W  =  96 - L  =  96 - 27  =  69

 

They won  69  of the games.

hectictar  Oct 20, 2017
Sort: 

1+0 Answers

 #1
avatar+5227 
+2
Best Answer

Let's call the number of wins  " W ", and the number of losses  " L ".

 

There are  96  games altogether, so....       W + L  =  96

 

The number of wins is 15 more than twice the number of losses, so....     W  =  15 + 2L

 

W + L  =  96

                                      We can substitute  15 + 2L  in for  W  since  W  =  15 + 2L .

15 + 2L + L  =  96

                                      Subtract  15  from both sides.

2L + L  =  96 - 15

                                      Combine like terms.

3L  =  81

                                      Divide both sides by  3 .

L  =  27

 

They lost  27  of the games.

 

Remember, there are 96 games total...   W + L  =  96   →  W  =  96 - L  =  96 - 27  =  69

 

They won  69  of the games.

hectictar  Oct 20, 2017

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