+0  
 
0
112
3
avatar+6 

A particular committee needs one 7-grader and three 8-graders. If there are four 7-graders and six 8-graders applying to the committee, in how many ways can the committee be filled?  

liala  Aug 16, 2017
Sort: 

3+0 Answers

 #1
avatar+78719 
+2

 

This is a combinations problem

 

There are 4  seventh graders and we want to choose one of them......

The number of ways this can be done  =  C (4,1) = 4      (1)

 

There are  six eighth graders and we want to choose any three of them

The number of ways this can be done  = C(8,3)  = 56      (2)

 

 

So....the total possible committees  =  (1) * (2)   =  (4) * (56)  =  224 

 

 

 

cool cool cool

CPhill  Aug 16, 2017
 #2
avatar+6 
0

Thank you soo much CPhil, but unfortunately that isn't the correct answer. I am taking a Probability and Counting class on AOPS like Mellie was....

liala  Aug 17, 2017
 #3
avatar
0

Sir CPhill made a booboosmiley

 

C(4,1) = 4

C(6,3)  = 20

 

4 * 20 = 60

Guest Aug 17, 2017

5 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details