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A particular committee needs one 7-grader and three 8-graders. If there are four 7-graders and six 8-graders applying to the committee, in how many ways can the committee be filled?  

 Aug 16, 2017
 #1
avatar+98197 
+2

 

This is a combinations problem

 

There are 4  seventh graders and we want to choose one of them......

The number of ways this can be done  =  C (4,1) = 4      (1)

 

There are  six eighth graders and we want to choose any three of them

The number of ways this can be done  = C(8,3)  = 56      (2)

 

 

So....the total possible committees  =  (1) * (2)   =  (4) * (56)  =  224 

 

 

 

cool cool cool

 Aug 16, 2017
 #2
avatar+6 
0

Thank you soo much CPhil, but unfortunately that isn't the correct answer. I am taking a Probability and Counting class on AOPS like Mellie was....

 Aug 17, 2017
 #3
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0

Sir CPhill made a booboosmiley

 

C(4,1) = 4

C(6,3)  = 20

 

4 * 20 = 60

 Aug 17, 2017

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