+97 A piece of wire of length 10 m is to be cut into two pieces. One piece will be used to make a square and the other to make an equilateral triangle. What are the two lengths of wire required such that the total area enclosed is a minimum? Round all values to TWO decimal places.
Length for triangle = ? [correct answer is 5.65 m]
Length for square = ?[correct answer is 4.35 m]
Thanks. :)
+130081 This is similar to the problem I just worked....here's the graph here.....the "x" value is the part reserved for the triangle = about 5.7 m and the part reserved for the square = (10 - 5.7) = about 4.3 m
https://www.desmos.com/calculator/7lucvqfmfx
+130081 This is similar to the problem I just worked....here's the graph here.....the "x" value is the part reserved for the triangle = about 5.7 m and the part reserved for the square = (10 - 5.7) = about 4.3 m
https://www.desmos.com/calculator/7lucvqfmfx
