A plane leaves Heathrow airport at 07:25 and flies due north 280 km to Manchester.
It stays at Manchester for 50 minutes and then flies 210 km due west to Snowdonia.
The Planes flies at an average speed of 420 kmper hour
1. At the what time does the plane arrives in Snowdonia?
2. Calculate the shortest distance that the plane would need to fly to return from Snowdonia to Heathrow airport
We have a right triangle
1. One leg is 280 km and the other is 210 km
So......the time it takes to fly these two legs is [ 280 + 210 ] / 420 = 490/420 = 7/6 hours =
1 hr 10 min
Add the 50 minute stop and it arrives at 9:25
2. Using the Pythagorean Theorem the shortest distance back is
√ [ 280^2 + 210^2 ] = √122500 = 350 km