+8 A point (x,y) with integer coordinates is randomly selected such that \($0 \le x \le 8$\) and \($0 \le y \le 4$\). What is the probability that \($x + y \le 4$\)? Express your answer as a common fraction.
+130081 x = { 0, 1 , 2, 3 , 4, 5, 6, 7 ,8 }
y = { 0, 1, 2, 3, 4 }
There are 45 possible sums [ many repeated ]
The ones ≤ 4 are
x
0 can be paired with 5 y terms
1 can be paired with 4 y terms
2 can ve paires with 3 y terms
3 can be paired with 2 y terms
4 can be paired with 1 y term
So...the probability that x + y ≤ 4 is
[ 1 + 2 + 3 + 4 + 5] / 45 = 15 / 45 = 1 / 3
