+817 Help plz!
The equation $18+5x^2=20x + 20$ has two distinct solutions. If each solution is rounded to the nearest integer, and then these two integers are multiplied together, what is the result?
+758 5x^2-20x-2=0. Using the quadratic formula, we get (20+-sqrt(440))/10. We can turn this into (20+-2sqrt(110))/10, or (10+-sqrt(110))/5. I calculated both answers, and got 4 and 0. 4*0 = 0, so I think the answer is 0.
+129771 18 + 5x^2 = 20x + 20
Rearrange as
5x^2 - 20x - 2 = 0 divide through by 2
x^2 -10x - 1 = 0
x^2 -10x = 1 complete the square on x
x^2 - 10x + 25 = 1 + 25
(x - 5)^2 = 26
x -5 = sqrt (26) and -sqrt (26)
x = sqrt (26) + 5 → rounded = 10
x= -sqrt (26) + 5 → rounded = 0
Product = 10 * 0 = 0
