+208 Hey there!
I have my matrix A and b and have found the general solution for \(x\) of \(Ax=b\). The next question i have is to project the general solution onto the rowspace of \(A\). I have the orthogonal projector which i believe is \(P=A^T(AA^T)^{-1}A\), im just curious as to how i actually approach the projection. My general solution is \(x_g=\begin{bmatrix} 0 \\1 \\0 \end{bmatrix}+t\begin{bmatrix}-0.5 \\-0.5 \\1 \end{bmatrix}\)so do i just sub this into \(Proj_{rowspace(A)}(x_g) =Px_g\) and work from there? Or is there something else i need to do that im missing?
