+150 What is the probability that at least two of the faces match when you roll three fair six-sided dice? Express your answer as a common fraction.
+6248 \(P[\text{at least 2 match}]=\\ 1-P[\text{none match}] = \\ 1-\dfrac{\dbinom{6}{3}3!}{6^3} = \\ 1 -\dfrac 5 9 = \\ \dfrac 4 9\)
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+128475 Here's another way to see this
P(at least two match) = 1 - P(that none match)
Note....that for none to match....the first die has 6/6 a chance of showing any number.....the second has a 5/6 chance of not showing the first number...and the third die has a 4/6 chance of not showing either of the first two numbers
So....P(none to match) = (6/6)(5/6)(4/6) = 20/36 = 5/9
So....P (at least two match) = 1 - 5/9 = 4/9
