is there a square, when multiplied by 3, is still a square?
3x = y
where 'x' and 'y' are both squares
I don't think so, sorry!
If your numbers are all integers then the answer is no, because sqrt(3) is irrational. If they can be reals, then yes: (sqrt(3)*a)2 = b2, for which there are an infinite number of solutions.
