+0  
 
0
296
1
avatar

A recruitment team is required to recruit 9 out of 15 applicant from 3 disciplines,each containing 5 applicants and not required to recruit more than 4 from each disciplines. In how many possible ways can the team make up her choice?

Guest Sep 4, 2014

Best Answer 

 #1
avatar+92624 
+5

I invite comment on this one.  

Let me see...

15 applicants.    5 sportA,     5 sportB    and     5 sportC

9 will be recruited and not more than 4 from any individual sport

possibilities

441      414      144        I think the number here is  5C4*5C4*5C1 = 3* 5*5*5 = 3*125 = 375

432   423  342   324   234   243   I think the number here is  6*5C4*5C3*5C2 = 6*5*10*10=6*500=3000

333    I think the number here is   1* (5C3)^3  =10^3 = 1000

 

So there seems to be 10 ways that the numbers from each sport can be chosen.

I think there are  375+3000+1000=4375 different ways that the 9 can  be selected.      

Melody  Sep 7, 2014
 #1
avatar+92624 
+5
Best Answer

I invite comment on this one.  

Let me see...

15 applicants.    5 sportA,     5 sportB    and     5 sportC

9 will be recruited and not more than 4 from any individual sport

possibilities

441      414      144        I think the number here is  5C4*5C4*5C1 = 3* 5*5*5 = 3*125 = 375

432   423  342   324   234   243   I think the number here is  6*5C4*5C3*5C2 = 6*5*10*10=6*500=3000

333    I think the number here is   1* (5C3)^3  =10^3 = 1000

 

So there seems to be 10 ways that the numbers from each sport can be chosen.

I think there are  375+3000+1000=4375 different ways that the 9 can  be selected.      

Melody  Sep 7, 2014

12 Online Users

avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.