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A rectangle’s length is 9 feet shorter than three times its width. The rectangle’s perimeter is 222 feet.

 

Find the rectangle’s length and width.

 Mar 25, 2021
 #1
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We can solve this with a system of equations.

 

Let l represent the rectangle's length.

Let w represent the rectangle's length.

 

We know that:

l = 3w - 9

and 

 

Perimeter = 222

Since the perimeter is simply 2(l+w);

2(l+w) = 222

l + w = 111

 

Now substitute in 3w +9 into l + w = 111:

l + w = 111

(3w - 9) + w = 111

4w - 9 = 111

4w = 120

w = 30

 

l = 3w - 9

l = 3(30) - 9

l = 90 - 9

l = 81

 

Therefore the length is 81 ft, and the width is 30 ft.

 Mar 25, 2021

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