A rectangle’s length is 9 feet shorter than three times its width. The rectangle’s perimeter is 222 feet.

Find the rectangle’s length and width.

liz54321 Mar 25, 2021

#1**0 **

We can solve this with a system of equations.

Let l represent the rectangle's length.

Let w represent the rectangle's length.

We know that:

l = 3w - 9

and

Perimeter = 222

Since the perimeter is simply 2(l+w);

2(l+w) = 222

l + w = 111

Now substitute in 3w +9 into l + w = 111:

l + w = 111

(3w - 9) + w = 111

4w - 9 = 111

4w = 120

w = 30

l = 3w - 9

l = 3(30) - 9

l = 90 - 9

l = 81

Therefore the **length is 81 ft**, and the **width is 30 ft**.

ArithmeticBrains1234 Mar 25, 2021