+409 A rectangle’s length is 9 feet shorter than three times its width. The rectangle’s perimeter is 222 feet.
Find the rectangle’s length and width.
+91 We can solve this with a system of equations.
Let l represent the rectangle's length.
Let w represent the rectangle's length.
We know that:
l = 3w - 9
and
Perimeter = 222
Since the perimeter is simply 2(l+w);
2(l+w) = 222
l + w = 111
Now substitute in 3w +9 into l + w = 111:
l + w = 111
(3w - 9) + w = 111
4w - 9 = 111
4w = 120
w = 30
l = 3w - 9
l = 3(30) - 9
l = 90 - 9
l = 81
Therefore the length is 81 ft, and the width is 30 ft.
