A rectangle with positive area has length represented by the expression 3x2 + 2x - 4 and width by x2 +1. Write expressions in terms of x for the perimeter and area of the rectangle. Give your answers in standard polynomial form and show your work.
So, for the area, we have: \(3x^2+2x-4*x^2+1=-x^2+2x+1 \)
And, for the perimeter, we have: \(2\left(3x^2+2x-4\right)\cdot \:2\left(x^2+1\right)=4\left(3x^2+2x-4\right)\left(x^2+1\right)\)