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A rectangle with positive area has length represented by the expression 3x+ 2x - 4 and width by x2 +1. Write expressions in terms of x for the perimeter and area of the rectangle. Give your answers in standard polynomial form and show your work.

GAMEMASTERX40  Jun 3, 2018
edited by GAMEMASTERX40  Jun 3, 2018
 #1
avatar+3189 
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Area: length*width

Perimeter= 2l+2w


So, for the area, we have: \(3x^2+2x-4*x^2+1=-x^2+2x+1 \)

And, for the perimeter, we have: \(2\left(3x^2+2x-4\right)\cdot \:2\left(x^2+1\right)=4\left(3x^2+2x-4\right)\left(x^2+1\right)\)

smileysmiley

tertre  Jun 3, 2018
 #2
avatar+9644 
+2

A rectangle with positive area has length represented by the expression 3x2 + 2x - 4 and width by x2 +1. Write expressions in terms of x for the perimeter and area of the rectangle. Give your answers in standard polynomial form and show your work.

 

laugh

Omi67  Jun 3, 2018

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