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3 cards are chosen at random from a standard 52-card deck. What is the probability that they can be arranged into a group of three consecutive cards, all of the same suit? For this problem, an Ace can either come before a 2 or after a King, but not both (so A23 and QKA both count, but KA2 doesn't).

 Jun 23, 2021
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Next time please include the address of the original post, preferably as a link.   wink

 

there are 52C3=22100  ways to chose 3 cards

 

three in a row are

A23

234

345

456

567

678

789

89 10

9 10 J

10 JQ

JQK

QKA

there are 12 of them for each suit which makes 48 altogether.

 

48/22100 = 12 / 5525

 Jun 26, 2021
edited by Melody  Jun 26, 2021

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