3 cards are chosen at random from a standard 52-card deck. What is the probability that they can be arranged into a group of three consecutive cards, all of the same suit? For this problem, an Ace can either come before a 2 or after a King, but not both (so A23 and QKA both count, but KA2 doesn't).
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there are 52C3=22100 ways to chose 3 cards
three in a row are
9 10 J
there are 12 of them for each suit which makes 48 altogether.
48/22100 = 12 / 5525