A rock is thrown into the air. It's height is given by the functionh(t) = -16t^2+ 64t + 17 where his measured in feet and t in seconds.
What is the height of the rock after 1 second?
At what time is the rock the highest?
t=
What is the highest the rock goes?
When does the rock hit the ground?
+37157 h(t) = -16t^2+ 64t + 17
put in t = 1 and calculate the height at 1 second
Highest point occurs a t t = -b/2a where b = 64 and a = -16 use this value of 't' in the equation to calculate the highest point
When the rock hits the ground h = 0
sooooo 0 = -16t^2 + 64 t + 17 use Quadratic Formula to find 't' values (throw out the negative 't' value)
quadratic formula a = -16 b = 64 c = 17
\(t = {-b \pm \sqrt{b^2-4ac} \over 2a}\) plug and play ! 
+37157 h(t) = -16t^2+ 64t + 17
put in t = 1 and calculate the height at 1 second
Highest point occurs a t t = -b/2a where b = 64 and a = -16 use this value of 't' in the equation to calculate the highest point
When the rock hits the ground h = 0
sooooo 0 = -16t^2 + 64 t + 17 use Quadratic Formula to find 't' values (throw out the negative 't' value)
quadratic formula a = -16 b = 64 c = 17
\(t = {-b \pm \sqrt{b^2-4ac} \over 2a}\) plug and play !
