A row of Pascal's triangle reads \[1,n,\ldots,n,1\] The arithmetic mean of the entries in this row of Pascal's triangle is $2048$. Find $n$.
This question only makes sense if the first row of Pascal's triangle is taken to be 1 1 (the first row is often given as just the number 1 on its own). Given this then the sum of numbers in row n is 2n and there are n+1 numbers so the arithmetic mean is 2n/(n+1). This equals 2048 when n = 15.
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This question only makes sense if the first row of Pascal's triangle is taken to be 1 1 (the first row is often given as just the number 1 on its own). Given this then the sum of numbers in row n is 2n and there are n+1 numbers so the arithmetic mean is 2n/(n+1). This equals 2048 when n = 15.
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